Problem of the Day


If x,y\neq0 and x\sqrt{12}+y\sqrt{51}=\sqrt{z}(2x+y\sqrt{17}), what is the value of z?

A. \sqrt{3}
B. 2
C. 3
D. \sqrt{5}
E.  7

Reveal Answer

Answer

C. 3

See the Solution

Solution

[latexpage]

$x\sqrt{12}+y\sqrt{51}=\sqrt{z}(2x+y\sqrt{17})$

On the left side, simplify $\sqrt{12}$ to $2\sqrt{3}$. Also, note that $\sqrt{51}$ can be written as $\sqrt{3}\sqrt{17}$. So the left side becomes $2x\sqrt{3}+y\sqrt{3}\sqrt{17}$. Now factor a $\sqrt{3}$ from the left side to get $\sqrt{3}(2x+y\sqrt{17})$. To make this match the right side, it must be true that $z=3$.


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